问题:要在Datagrid中显示时间为2.08小时,我在SQL中这样处理:SELECT 125 / 60.00 AS float 但在Datagrid中显示为2.083333,请问如何写代码只保留两位小数点2.08? ______________________________________________________________________________________________ 答1: float(7,2) 2表示保留两位小数 ______________________________________________________________________________________________ 答2: float(8,2)?在哪写呢? ______________________________________________________________________________________________ 答3: 在datagrid的属性生成器中,列,数据格式设置表达式加上: {0:f2} ______________________________________________________________________________________________ 答4: 1.在sql语句中:select convert(dt,numeric(5,2)) from
2.在datagrid的绑定列的数据格式一栏添加:{0:f2} ______________________________________________________________________________________________ 答5: 任选其一 ______________________________________________________________________________________________ 答6: 是这样写吗“select convert(125/60.00,numeric(5,2)) from ”? 这样写运行时出错啦...
______________________________________________________________________________________________ 答7: select round(125/60.00,2) ______________________________________________________________________________________________ 答8: select cast(125/60.00 as numeric(5,2)) ______________________________________________________________________________________________ 答9: Thank you. 请问使用round和cast有何区别? ______________________________________________________________________________________________ 答10: 把数据库中的相应字段设置为decimal,然后把他的小数位改成2 ______________________________________________________________________________________________ 答11: 在Datagrid的OnItemDataBound事件中写e.item.cell[0].text = float(7,2).Tostring() 就在dg中第0列中转换并显示出来了
______________________________________________________________________________________________ 答12: 方法确定很多 1、设计字段时类型为numeric,小数位设置成2 2、在sql语句中转换:select convert(字段,numeric(18,2)) AS 字段Ex from 表 如果是datagrid绑定列<Columns>,则<asp:BoundColumn DataField="字段Ex " />
3、在datagrid的绑定列的属性中这样使用 <asp:BoundColumn DataField="字段" DataFormatString ="{0:f2}" /> |